1. For the known function z=√(2x/3)+7y, please express x with z and y (express x as an expression about z and y).

Due to the writing format, the default (2x/3)+7y is below the root sign.

Both sides of the expression are squared at the same time: z? = 2x/3+7y = = = = & gt； x=(z？ -7y)*3/2

2. Solve the fractional equation about x: the numerator and denominator are a bit confusing.

There's only one way. First divide the two sides of the molecule into simple ones, and then go to the denominator for calculation. Finally, it will lead to the removal of roots with denominator of 0.

3. Simplify the following expression. (General division can be made, and similar projects can also be merged. )

a、3/(q-p)-4/q = 3q/[(q-p)q]-4(q-p)/[(q-p)q]

=[3q-4(q-p)] /[(q-p)q]

=(4p-q)/[(q-p)q]

Other questions are the same, please calculate for yourself. Please ask questions if you don't understand. Thank you.