f'(- 1) = 5/2

The second is to solve ternary linear equations.

-27/8 + 9B/4 - 3C/2 + D = 0

27/64 + 9B/ 16 + 3C/4 + D = 0

27 + 9B + 3C + D = 0

The third formula-the second formula is 189+60B+ 16C = 0.

The third formula-27+6b+4c of the first formula = 0.

Then B = -9/4 and C = -27/8.

Substituting the third formula, we get D = 27/8.

Then B+C+D = -9/4.

y = y？ /y？ = (2+11I)/(3+4 I) = (2+11I) (3-4 I)/25 = 2+I, that is, A = 2 and B =/kloc-.

777 (octal) = 7*8? +7*8+7 = 5 1 1

666 (hexadecimal) = 6*7? +6*7+6 = 342

555 (hexadecimal) = 5*6? +5*6+5 = 2 15

The sum of the three is 1068.

1068/5 = 2 13……3

2 13/5 = 42……3

42/5 = 8……2

8/5 = 1……3

1/5 = 0…… 1

1068( 10 radix) = 13233(5 radix)

This is a continuous score.

42/ 17 = 2……8

That is 42/17 = 2+8/17 = 2+1/(17/8).

17/8 = 2…… 1

That is 17/8 = 2+ 1/8.

So 42/17 = 2+8/17 = 2+1/(17/8) = 2+1/(2+1/8).

P=2，Q=2，R=8

P+Q+R= 12