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20 13 Zhanjiang two-mode mathematics
In the reading algorithm, the output (x, y) of the flowchart is (1, 1), and n =1; (2,2),n = 2; (3,3),n = 3; ; (4,4),n = 4; (5,5),n = 5; (6)n=6) n = 6 ends the loop.

That is, the output (x, y) has (1,1); (2,2); (3,3); ; (4,4); (5,5); (6, 6), there are inequality groups where (2, 2) and (3, 3) * * * 2 satisfy.

So the answer is: 2