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Extending D to P makes DP=MB, and connecting AP can easily get ⊿ ADP ≌⊿ ABM = "∠ 1 = ∠ 2, PD=MB and ∠MAN=45, then ∠ 1+. =∠PAN=45 and AP=AM, easy to handle ⊿NAP≌⊿AMN? = "pn = Mn triangle MNC perimeter L=MC+NC+MN=? MC+NC+PN=？ MC+NC+DN+PD=？ MC+NC+DN+MB=CD+CB= 1/2 square perimeter.

The next question is the finale of the 2009 Fuzhou senior high school entrance examination mathematics paper. Some formulas can't be typed? You can find the answer yourself. Very convenient

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