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Congruent triangles proof of mathematics in the first volume of the second day of junior high school
1. Because AB=AC, ∠BAE=∠CAF, ∠AFC=∠BEA=90 degrees and △BEA are all equal to △CFA, AF=AE, BF=AB-AF, CE=AC-AE, so BF =

BF=CE, ∠FDB=∠EDC, ∠BFD=∠CED=90 degrees, so △BFD is all equal to △CED, so DB=DC.

2. The topic should have other conditions. Point o has nothing to do with AB=AC in ABC.