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Descartes product discrete mathematics
Note that A={0, 1}, then a× a = {

Empty relation φ;

{ & lt0,0 & gt; };

{ & lt0, 1 & gt; };

{ & lt 1,0 & gt; };

{ & lt 1, 1 & gt; };

{ & lt0,0 & gt; ,& lt0, 1 & gt; };

{ & lt0,0 & gt; ,& lt 1,0 & gt; };

{ & lt0,0 & gt; ,& lt 1, 1 & gt; };

{ & lt0, 1 & gt; ,& lt 1,0 & gt; };

{ & lt0, 1 & gt; ,& lt 1, 1 & gt; };

{ & lt 1,0 & gt; ,& lt 1, 1 & gt; };

{ & lt0,0 & gt; ,& lt0, 1 & gt; ,& lt 1,0 & gt; };

{ & lt0,0 & gt; ,& lt0, 1 & gt; ,& lt 1, 1 & gt; };

{ & lt0,0 & gt; ,& lt 1,0 & gt; ,& lt 1, 1 & gt; };

{ & lt0, 1 & gt; ,& lt 1,0 & gt; ,& lt 1, 1 & gt; };

{ & lt0,0 & gt; ,& lt0, 1 & gt; ,& lt 1,0 & gt; ,& lt 1, 1 & gt; }。