(1) If there is no 1 in the four numbers, there are two choices: 2 and 4. If the other three bits are randomly arranged, there are 3X2=6 kinds; So there are 2X6= 12 kinds of * *.
(2) If there is 1 in the four numbers, and if 1 can only be thousands or hundreds, there are two choices; There are two choices: 2 and 4. 2; The remaining two bits can be randomly arranged among the remaining three bits, so there are 3X2=6 kinds; So there are 2X2X6=24 kinds.
So the general arrangement method is: 12+24=36.