Master of mathematical probability, please come in ~ ~ to explain the process in detail.

Bet at least 2 times and at most 5 times.

p=55%，q=45%

(O means win, X means lose)

The probability of losing twice is qq.

Gambling has a situation of losing three times: OXX, and the probability is pqq.

In one case, four bets are lost: XOXX, probability pqqq.

There are three situations when you lose five times: XOXOX, XOOXX, OXOXX, and the probability is 3 ppqq.

Then the probability of losing is QQ+PQQ+PQQ+3PQQ.

No win or lose will only happen if you gamble four times: OOXX, the probability is ppqq.

Then the winning probability is1-(QQ+pqq+pqq+3pppqq+ppqq).

The result is 0.4920540625 (computer calculation).