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The sum of two numbers, A and B, is 540, A minus 120 and B plus 40. A is exactly three times that of B, so how much is A more than B?
540- 120+40=460

460/(3+ 1)= 1 15

1 15-40=75 B

115 * 3+120 = 465 or 540-75 = 465A.

This is an extension of the doubling problem. A minus 120 and b plus 40, the sum of the two numbers is now 540- 120+40=460.

Now B is 460 ÷ (3+1) =115, and now A is 1 15×3=345.

Original a is 345+ 120=465, and original b is 1 15-40=75.

It turns out that the number of A is 465-75=390.

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