The Solution of Mathematics Definition Domain in Senior One.

The domain of f(x) is also-1/2x.

3, where the value of x is obtained from "2", and the domain of f(x) is-1/2x.

3, the value of x is [1,

Therefore, 3/2≤- 1/2x.

3≤5/2, if f(- 1/2x+3)=f(t), the range of t is [3/2,

5/2]

The reason for this is that from the perspective of the relationship between a function and its domain,

F(x)-X, that is, the domain of F(x) refers to the range of X;

f(- 1/2x+3)

-1/2x+3, then the range of f (-1/2x+3)=f(t), and t=- 1/2x+3 is not the range of t?

Don't you get it, f(t)

T, obviously, t is the independent variable of the function f(t), and the value of t is the domain of f(t).

In that case, change t into x, f(x).

X is the quantity used to represent the self-variation of a function.

Therefore, we can get that the domain of f(x) is t=- 1/2x+3, that is, [3/2,

5/2]

So in the third question, the domain of f(x) is obtained as follows: [3/2,

5/2]

Find the definition domain of f(2x- 1), and conversely, let t=2x- 1, and f(2x- 1)=f(t).

Since the value range of t is: [3/2,

5/2], that is, the value range of 2x- 1 is [3/2,

5/2]?

Therefore, according to the solution of inequality, we can find the value range of x in 2x- 1.

It is the domain of f(2x- 1).

Having said that, I can only go so far. I hope I can help you!