(Question): What is the probability of delivering a manuscript through employment?
Let A stand for the event: the manuscript can pass the review of two preliminary evaluation experts;
B stands for event: the manuscript has just passed the examination of a preliminary expert;
C stands for event: the manuscript can pass the review of the review experts;
D stands for event: the manuscript was hired.
Then D=A+B*C
P(A)=0.5*0.5=0.25,P(B)=2*0.5*0.5=0.5,P(C)=0.3
P(D)=P(A+B*C)
=P(A)+P(B)*P(C)
=0.25+0.5*0.3=0.40
(2): What is the probability that at least two of the four manuscripts will be accepted?
Let A0 represent the event: 1 of the 4 manuscripts were not hired:
A 1 indicates the event: exactly 1 of the four manuscripts was hired:
A2 represents an event: at least two of the four manuscripts were hired.
p(a0)=( 1-0.4)^4=0. 1296
p(a 1)=4*0.4*( 1-0.4)^3=0.3456
P(A0+A 1)=P(A)+P(A 1)
=0. 1296+.3456=0.4752
P(A2)= 1-P(A0+a 1)= 1-0.4752 = 0.5248。