Solution: As shown in the figure, it can be obtained from the nature of rotation: ∠ a ′ c ′ b = ∠ ACB = 45, BC = BC' ′,

∴∠bc′c=∠acb=45，

∴∠cbc′= 180-∠BC′c-∠ACB = 90，

BC = 6，

∴cc′=2bc=62，

AD⊥BC with point A as point D,

∫∠ACB = 45，

△ ACD is an isosceles right triangle,

Let AD=x, then CD = X.

∴BD=BC-CD=6-x，

At △ABD, AD2+BD2=AB2,

∴x2+(6-x)2=52，

Solution: x 1=6+ 142, x2=6? 142 (irrelevant),

∴AC=6+ 142×2=32+: I praised it and stepped on it. What is your evaluation of this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and provide free professional consultation through Baidu Law Professional Edition. Other similar problems occurred on July 29th, 2022 at △ABC, ab = BC = 2 and angle ABC = 120. Rotate △ABC clockwise around point B for one degree (acute angle △ABC, AB = 4, BC = 5, ∠ ACB = 45) and rotate △ABC counterclockwise around point B to get △. When C 1 point forms an acute angle with the line 382012-1-04, △ABC, AB=4, BC=5, ∠ ACB = 45, rotate △ABC counterclockwise around point B to get △ A. AB=BC=6, rotate △ABC clockwise around point B by an angle α(0