-D3 * e 1-D2 * E2-d 1 * E3-C3 * E4-C2 * E5-c 1 * E6-B3 * E7-B2 * E8-b 1 * e9-a3 * e 10-a2 * e 1 1
-a 1 * e 12+e 1+E2+E3+E4+E5+E6+E7+E8+e9+e 10+e 1 1+e 12 & lt; = 0
Then use integer programming to solve this problem, and get:
e 1= 1,e2= 1,e3= 1,e4= 1,e5= 1,e6= 1,e7= 1,e8= 1,e9= 1,e 10=4,e 1 1 = 0
Therefore, when E 1 = 1, E2 = 1, E3 = 1, E4 = 1, E5 = 1, E6 = 1, E7 =/. When e 12=2, the formula holds, while e 1, e2, E3...E 12 are positive integers respectively.