Then A is 4x, B is 7x/3, and C is 5x/3 4x+7x/3+5x/3=360 x=45.
The water is 45 centimeters deep.
How many books does Xiaogang have? Xiaohua borrows half and adds one, Xiaoming borrows half and adds two, Xiaofeng borrows half and adds three, and finally Xiaogang has two left, so Xiaogang has two left. So how many books does Xiaogang have?
Test center: inverse problem. Analysis: This problem needs to be pushed forward step by step from the problem. The two books and three books left by Xiaogang are half of those borrowed by Xiaoming, so that we can find out the number borrowed by Xiaoming and the number borrowed by Xiaohua, and then we can find out the original number of Xiaoming. Solution: Xiao Feng had a book before he borrowed it: (2+3) ÷ (65438).
(10+2) ÷ (1-1/2) = 24 (this), Xiao Gang's original work:
(24+1) ÷ (1-1/2) = 50 (Ben). A: Xiaoming has 50 original books, so the answer is 50.
The number of A is more than that of B 1/3, and the number of B is less than that of A? The number B is the unit "1" and the number A is: 1+0/3 = 4/3. The number b is less than the number A: 1/3 ÷ 4/3 = 1/4.
There are several pears and apples. The number of pears is 5/3 less than that of 17, and the number of apples is 7/4 less than that of 3 1. So what are the numbers of pears and apples?
Solution: Let the total number be 35X.
Then pears have 35x * 3/5-17 = 21x-17 apples have 35x * 4/7-31= 20x-31.
So there are 265438 pears +0× 6- 17 = 109 apples and 20×6-3 1=89 apples.
There is a fraction whose denominator is 4 more than the numerator. If both the numerator and denominator add 9, the score is 7/9. What is the score?
Let the numerator be x and the denominator be x+4, then; (X+9)/(X+ 13)= 7/9； X = 5 A: the molecule is 5/9.
Fold a rope into 5 strands and 6 strands respectively, with 5 strands being 20 cm longer than 6 strands. How long is this rope? The length of this rope is 20( 1/5- 1/6)= 600 cm.
Xiaoping's age this year is 65438+ 0/3 of her mother's. Two years ago, the age difference between mother and daughter was 24 years old. How old is Xiaoping after four years?
Solution: Let Xiaoping be X years old this year, then mother is 3X years old 3x-2 = x-2+24 3x = x+24 2x = 24 x =12 this year.
The final answer: 12+4= 16 (years old)
There is a basket of apples. A takes half one less, B takes the remaining half one more, C takes the remaining half, and there is one left. If each apple is worth 1 yuan 9.88 cents, how much is this basket of apples worth?
C takes the remaining half, and there is one left, that is to say, before C takes 1+ 1=2 B takes the remaining half and more than one, then before B takes (2+ 1)*2=6 A takes less than half, then A takes the previous time (6-1)
The following is the process of solving the problem: let this bag of apples be X, then the number of apples taken by A is X/2- 1.
The number of apples taken by B is (X-X/2+ 1)/2+ 1.
The number of apples taken by C (also the remaining number) is: total -A takes -B takes,
That is, x-x/2+1-(x-x/2+1)/2-1/2 =1Solve the equation, and X= 10.
Xiaohui took part in the World Youth Olympic Mathematical Gold Cup by plane. Outside the window, the city is a picturesque blue ocean. He saw that the sea of clouds accounted for 1/2 of the whole map, covered an island 1/4, and bare islands accounted for 1/4 of the whole map. How much part of the whole sea surface should be covered?
Let the island be X, the whole picture be Y and the sea cover be Z. According to the meaning of the question, 3/4*x= 1/4*y y=3x.
Then the sea surface is 3/4 * X.
z = 1/2 * 3x- 1/4 * x = 5/4 * x
And the sea surface is 2x.
Except for not using XY, just using arithmetic. If it doesn't work, you can only use X. The answer is that the island occupies the whole map =1/4 ÷ 3/4 =1/3; Marine map = 1- 1/3=2/3.
Covered sea area = (1/2-1/4 *1/3) =1/2-12 = 5/12.
A monkey picked a bunch of peaches:
On the first day, I ate a seventh of this pile of peaches; The next day I ate one-sixth of the remaining peaches; On the third day, I ate the remaining one-fifth of peaches; On the fourth day, I ate a quarter of the remaining peaches; On the fifth day, I ate a third of the remaining peaches; I ate half the remaining peaches on the sixth day;
There are still 12 peaches left, so what is the total number of peaches eaten by monkeys on the first day and the second day?
Let the total number of peaches be X.
1/7x times 6/7x times 5/6x times 4/x5 times 3/4x times 2/3x times121/7x =12x = 84.
84X 1/7= 12 on the first day and 72x1/6 =12 = 24 on the second day.
It takes 5 hours for A to go from place A to place B, and the speed for B to go from place B to place A is 5/8 of that of A. Now both A and B start from place A and place B at the same time, face to face. Meet on the road and move on. A returned immediately after arriving at B, and B returned immediately after arriving at A, and met again on the way. If the two meeting points are 72 kilometers apart, how many kilometers are A and B apart?
Solution: Let the distance between AB and AB be 1.
Then the speed of A is 1/5, the speed of B is (1/5)*(5/8)= 1/8, and the speed ratio of A and B is A: B = (1/5): (1).
When they met for the second time, they went three times.
Then the stroke of A is 3*8/ 13=24/ 13, and the difference between the two strokes is 2-24/ 13=2/ 13, so AB is 72/(8/13-2.
Divide 100 people into four teams. The number of the first team is 4/3 times that of the second team, and the number of the first team is 5/4 times that of the third team. How many people are there in the four teams?
Let the first team be 1, the second team be 3/4 and the third team be 4/5, then the sum of the three teams is 1+3/4/5 = 5 1/20, which shows that the number of the first team should be a multiple of 20.
The first team is at 20 o'clock, 20+15+16+49 =100; When the first team is 40 years old, 40+30+32 >: 100 give up.
So 20+15+16+49 =100 is the only solution, that is, the fourth team has 49 people.
Ps: the first team can also be set to k people, and the sum of the three teams = 51k/20; Obviously, k should be a multiple of 20. Only when k=20 can there be a solution.
Tickets for this football match are each 15 yuan. After the price reduction, the audience increased by half and the income increased by one fifth. How much is the price reduction per ticket?
The audience doubled, that is, only one person came to see it, and now it is two people. The income has increased by 1/5, that is, the total fare for two people is more than that for a single person 1/5, that is, each person15 * (1+1/5) =18 yuan.
Answer:15-15× [(1+1/5) ÷ (1+1/2) =15-/kloc.
A: One ticket is reduced in price, 3 yuan.
So fill in: 3. Comments: The key to this problem is to find the unit "1", find the quantity corresponding to the unit "1", find the unit "1", tell the unit "1" by division, and find the score of the unit "1".
Before the price reduction, it is assumed that there are 10 audience, and the income is l =15×10 =150 (yuan). Now 15 people, down by x yuan.
( 15-x)× 15 = 150×( 1+ 1/5)225- 15x = 180 15x = 45x = 3，
Reduce the price, 3 yuan.
Party A, Party B and Party C cooperate to process a batch of parts. Party A processes 20 more parts than Party B, and the parts processed by Party C are the parts processed by Party B..
4/5 of the parts processed by Party A is 5/6 of the total parts processed by Party B and Party C. How many parts are processed by Party A, Party B and Party C respectively? Set: A process x, b process X-20, c process 4/5 (x-20) 5/6 [x-20+4/5 (x-20)] = x 5/6 [x-20+4x/5-16] = x 5/6.
C treatment = 40× 4/5 = 32
A factory has 27 masters with 40 apprentices, and each master can take one, two or three apprentices. If there are twice as many masters with one apprentice as other masters, how many masters with two apprentices?
Suppose there are 2x masters with one apprentice, then 2x+(2x)/2=27 gives x=9, 2x= 18 and there are y masters with two apprentices, then the master with three apprentices is 27- 18-y=9-y, and the equation can be obtained.
The solution of18 *1+y * 2+(9-y) * 3 = 40 gives y=5.
Zhang, Wang and Li each have 54 yuan. Zhang used 3/5 of his own money, Wang used 3/4 of his own money and Li used 2/3 of his own money, and each bought the same pen. So how much money do Z Ryan and Lee have left?
Because "each bought the same pen", the money spent is the same, so the price of the pen can be set to X yuan, and the equation is as follows.
X/(3/5)+x/(3/4)+x/(2/3)=54，x= 12，
Then calculate the remaining amount of Zhang, Wang and Li according to the ratio of the remaining amount to the used amount, as shown below:
12*(( 1-3/5)/(3/5))=8、 12*(( 1-3/4)/(3/4))=4、 12*(( 1-2/3)/(2/3))=6
Zhang's 3/5 is equivalent to Wang's 3/4 and Li's 2/3. It can be seen that the ratio of three people with money is Zhang: Wang = 3/4: 3/5 = 5: 4, Wang: Li = 2/3: 3/4 = 8: 9: Wang: Li = 10: 8.
It turns out that Li's money is different: 20 yuan, 16 yuan, 18 yuan. They each have 8 yuan, 4 yuan and 6 yuan.
Three identical cups numbered 1, 2 and 3 are filled with half a cup of liquid respectively. 1 There is 100g sugar in the No.2 cup, and 100g salt in the No.3 cup. First, pour half of the liquid in the 1 cup and the 1/4 liquid in the No.3 cup into the No.2 cup, then stir evenly, then pour out 2/7 to 1 cup from the No.2 cup, and then pour out the remaining liquid in the 1/7 to No.3 cups. Q: What is the ratio of salt content to sugar content in each cup at this time?
You have to separate the volume from the weight, and I will calculate the remaining amount in the cup according to the number of times you pour it.
First pour, 1st cup: 50g sugar, 1/4 liquid; The second cup: 50 grams of sugar, 25 grams of salt, 7/8 liquid; The third cup: 75 grams of salt, 3/8 liquid.
Second pour, 1st cup: 50+50x2/7 sugar, 25x2/7 salt, 1/2 liquid; The second cup: 50x:5/7 sugar, 25x5/7 salt and 5/8 liquid.
Pour the second cup for the third time: 50x4/7 sugar, 25x4/7 salt and 3/4 liquid; Cup 3: 50x 1/7 sugar, 75+25x 1/7 salt, 1/2 liquid.
So the salt content: 1st cup (50/7) salt /( 1/2) liquid =100/7; No.2 cup (100/7) salt /(3/4) liquid = 400/21; Cup 3 (75+25/7) salt /( 1/2) liquid =1075/7; So the ratio is 15: 18: 129.
Sugar content: 1st cup (50x9/7) sugar /( 1/2) liquid = 900/7; The second cup of (50x4/7) sugar /( 1/2) liquid = 400/7; 3rd cup (50/7) sugar /( 1/2) liquid =100/7; So the ratio is 9:4: 10.
Grade six students in a school 152 students. If you choose111boys and 5 girls to participate in the science and technology group, the remaining number of boys and girls is exactly equal. How many boys and girls are there in the sixth grade?
There are x boys and 152-x girls (101) x =152-x-5x = 77.
There are 77 boys and 75 girls.