Solution: 2 (radical X+ radical (y- 1)+ radical (z-2)) = x+y+z.
X & gt=0,y & gt= 1 . z & gt; =2
Root number x+ 1+(y- 1)+2 root number (y- 1)+ 1+z-2-2 root number (z-2)+ 1=0.
(radical number X- 1) 2+[ (radical number (Y- 1)- 1]2+[ radical number (Z-2)- 1] 2 = 0.
So we get the radical number x- 1=0 and the radical number Y- 1- 1 = 0.
Root number (z-2)- 1=0
x= 1,y=2,z=3
The square root of yz-2x = the square root of (2 * 3 -2) =2 or -2.
The result is 2 or -2.