2 (root number AIX+ root number y- 1+ root number z-2)=x+y+z, find the square root of yz-2 AIX.

Solution: 2 (radical X+ radical (y- 1)+ radical (z-2)) = x+y+z.

X & gt=0，y & gt= 1 . z & gt； =2

Root number x+ 1+(y- 1)+2 root number (y- 1)+ 1+z-2-2 root number (z-2)+ 1=0.

(radical number X- 1) 2+[ (radical number (Y- 1)- 1]2+[ radical number (Z-2)- 1] 2 = 0.

So we get the radical number x- 1=0 and the radical number Y- 1- 1 = 0.

Root number (z-2)- 1=0

x= 1，y=2，z=3

The square root of yz-2x = the square root of (2 * 3 -2) =2 or -2.

The result is 2 or -2.