∵x? -? y? +? M=0 and y=? x? +? m
Will y=x? +? M is substituted into x 2+y 2-2x- 1 = 0.
Get x 2+(x? +? M) x 2+extends 2-2x- 1 = 0? x^2+2mx+m^2-2x- 1=0
That's two? x^2+(2m-2)x+m^2- 1=0
Make △ > 0 is (2m-2)2-4×2×(m2- 1)0.
The factorization is (m- 1)×? 【m- 1-4(m+ 1)】? ﹥0
That is (m- 1) (3m+5)-0.
m- 1¢0? Or? m- 1; 0
3m+5¢0
The solution is -5/3¢m 655438+0.