∵x？ -? y？ +? M=0 and y=? x？ +? m

Will y=x? +? M is substituted into x 2+y 2-2x- 1 = 0.

Get x 2+(x? +? M) x 2+extends 2-2x- 1 = 0? x^2+2mx+m^2-2x- 1=0

That's two? x^2+(2m-2)x+m^2- 1=0

Make △ > 0 is (2m-2)2-4×2×(m2- 1)0.

The factorization is (m- 1)×? 【m- 1-4(m+ 1)】？ ﹥0

That is (m- 1) (3m+5)-0.

m- 1￠0？ Or? m- 1； 0

3m+5￠0

The solution is -5/3￠m 655438+0.