Let's catch up in x hours (equivalent to the same distance when two cars catch up)

20x2+20X=60X

40X=40X

X= 1

2、

Suppose the meeting time is X.

It is equivalent to the time from catching up to meeting two cars.

When we caught up, both cars left.

60x1= 60km

The distance to B is 240-60= 180km.

The meeting distance is 180x2=360km.

(20+60)x X=(240-60x 1)x2

80X=360

X=4.5

Take the local train 20x4.5 = 90km km.

60+90 =150km

Meet at a distance of a 150km.