The zero point of the function obtained from the title is x 1=0, x2= 1, and the abscissa of the vertex is x= 1/2.

Then the ordinate is y=log2( 1/2)=- 1, and f (1/2) = a *1/2 * (11) =-.

That is f (x) = 4x (x-1) = 4 (x-1/2) 2-1.

2. Draw g(x)=|f(x)| It can be seen that when -m=0 or -m >; 1, that is, m=0 or m.