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Ermo 20 16 Chongming Mathematics Grade 3
1, parabola y=? X2+bx+c passes through point a (? 2,0)、B(4,0),

∴{? 4? 2b+c=0,? 16+4b+c=0, the solution is: {b=2, c=8,

∴y=? x2+2x+8。

2. For OH∑AC passing through point O and at point H,

∵A(? 2,0)、B(4,0),

∴OA=2,OB=4,AB=6,

∫D is the midpoint of OC,

∴CD=OD,

∵OH∨AC,

∴OHCE=ODCD= 1,

∴OH=CE,

∴CEAE=OHAE=BOBA,

∴CEAE=23.

3. point c is CF⊥AB, and the vertical foot is point f,

Let C(x,? X2+2x+8), and then F(x, 0),

∴AF=x+2,CF=? x2+2x+8,

∫ in Rt△AFC, tan∠CAB=CFAF=2,

∴? x2+2x+8x+2=2,

Solution: x=2,

∴C(2,8),

∴S△AOC= 12×2×8=8,

Connect OE so that s △ CDE = y.

OD = CD,

∴S△ODE=S△CDE=y,

∴S△OCE=2y,

∫CEAE = 23,

∴S△OCES△AOE=23,

∴S△OAE=3y,

∴S△OAC=5y,

∴5y=8,

∴y=85.

The area of CDE is 85.

Extended data:

Parabolic junior high school knowledge arrangement

1, parabola is an axisymmetric figure. The symmetry axis is a straight line x = -b/2a.

The only intersection of the symmetry axis and the parabola is the vertex p of the parabola. Especially when b=0, the symmetry axis of the parabola is the Y axis (that is, the straight line x=0).

2. The parabola has a vertex p, whose coordinates are: P (-b/2a, (4ac-b 2)/4a) When -b/2a=0, p is on the Y axis; When δ = b 2-4ac = 0, p is on the x axis.

3. Quadratic coefficient A determines the opening direction and size of parabola.

When a>0, the parabola opens upwards; When a<0, the parabola opens downward. The larger the |a|, the smaller the opening of the parabola.

4. Both the linear coefficient b and the quadratic coefficient a*** determine the position of the symmetry axis.

When A and B have the same number (ab>0), the symmetry axis is on the left side of Y axis;

When a and b have different numbers (i.e. AB

5. The constant term c determines the intersection of parabola and Y axis.

The parabola intersects the Y axis at (0, c)

6. Number of intersections between parabola and X axis

δ= b^2-4ac>; 0, parabola and x axis have two intersections.

When δ = b 2-4ac = 0, there are 1 intersections between parabola and X axis.

δ= b^2-4ac<; 0, the parabola has no intersection with the x axis. The value of x is an imaginary number (the reciprocal of the value of x =-b √ b 2-4ac, multiplied by the imaginary number I, and the whole formula is divided by 2a).