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Complete works of primary school mathematical formulas: sum and difference problems
The key to solve the problem is to convert the sum of two numbers into the sum of two large numbers (or the sum of two decimals), and then find another number.

Law of solving problems: (sum+difference) ÷2 = large number-difference = decimal.

(sum and difference) ÷2= decimal, and-decimal = large number.

For example, there are 94 workers in Class A and Class B in a processing plant, and 46 workers in Class A are temporarily transferred from Class B due to work needs. At this time, Class B has fewer 12 workers than Class A. How many workers are there in Class A and Class B respectively?

Analysis: From Class B to Class A, the total number of people has not changed. Now the number of class B is converted into two classes B, that is, 94- 12, which means that the current class B is (94- 12) ÷ 2 = 4 1 (people), and the class B should be 4650 before being transferred to 46 people.