p(k)=q(k)-2^k=0,0<； = k & lt=20 15, k∈Z (variable topic),

According to the remainder theorem, p (x) = ax (x-1) (x-2) ... (x-2015), a ≠ 0,

∴ Q(x) = p (x)+2 x, which contradicts "Q(x) is a polynomial of degree 20 15".

There is no solution to this problem.