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Ask a math problem in grade three: the calculation of acute trigonometric function (solve the problem in detail)! ! ! ! Urgent, please. .
First, sin60=cos30, so (sin? 60 - 2cos30 + 1)=(cos？ 30-2 cos 30+ 1)=(cos 30- 1)？
Then open the root sign, so it is cos 30- 1 = √ 3/2- 1, and the front tan 45-tan 60.
| tan45-tan60 | = tan60-tan45 = √ 3-1,so the original formula is = √ 3-1+√ 3/2-2.