1, root number 25=(5)

The square root of 2 and 9 is (3)

3, -0.5 is the square root of (-root number 0.25).

The square root of .4,0.169 is (plus or minus 13).

5,+-plus or minus 1/3 is the square root of a, then a=( 1/9).

6. If x=7 under the radical sign, then x=(49)

7. If a2=b, then B is the square number of A and A is the square root of B..

8. When x=5, the square root of (x-9)2 under the radical sign is (4).

Second, multiple choice questions

1, - 125 (-5)

The value of (-2)3 under the root numbers 2 and 3 is (-2).

3. The cube root is equal to its own number (plus or minus 1 and 0).

4. If (3x+2)3- 1=6 1/64, then x=( -0.25).

5. The cube root of a number is equal to the arithmetic square root of this number. Then this number is equal to (1 and 0).

6. If (x-2)2=9, then X is (5).

Third, answer questions.

1 has a square with a side length of 5cm and a rectangle with a length of 8cm and a width of 18cm. To make a square with an area equal to the sum of these two figures, how long should the side be? 2. Given that y=x3- 1 1, the arithmetic square root of y is 4, find the value of x .. 3, the radius of the ball r, the volume of the ball 500cm2, (v ball =4/3πr2), and find the value of r .. (π takes 3. 14. Given that a+2b=3 under the root number and 4a-2b=4 under the root number, find the value of a-b.

1, solution: area sum = square area+rectangular area = 5 * 5+8 *18 = 25+144 = 169 (square centimeter)169 square root is plus or minus/kloc-0.

2. Solution: Because the arithmetic square root of Y is 4, then substitute Y = 4 2 =16 into y=x3- 1 1.

16=x^3- 1 1 x^3=27 x = 3

3. Solution: V = 4/3π R3 = 500π R3 = 500 * 3/4R3 =1500/4π =159.236.

r= 10.928

4. Solution: a+2b=9 4a-2b= 16. It can be seen that 5a=25 a=5 b=2, so a-b=3.