Therefore, a=log3(x) (note: log3(x) stands for the base 3 logarithm of x), b=log4(x) and c=log6(x).
According to the inference of logarithm base formula, logm(n)×logn(m)= 1 (Note: the logarithm of n with base m and the logarithm of m with base n are reciprocal).
So 1/a=logx(3), 1/b=logx(4), 1/c=logx(6).
therefore
left = 2/a+ 1/b = 2 logx(3)+logx(4)= logx(3 2×4)= logx(36)
right = 2/c = 2 logx(6)= logx(6 ^ 2)= logx(36)
Visible, left = right.
Therefore: 2/a+1/b = 2/c.