The intersection of 3x-y- 1=0 is

( 1,2)

Because it is parallel to the straight line 5x-y+ 100=0.

, so the slopes are equal. The slope of 5x-y+ 100=0 is k=5.

So the linear equation is y-2=5(x- 1).

y-2-5x+5=0

y-5x+3=0

The intersection of 2,2x+y-8 = 0 and x-2y+ 1=0 is

(3,2)

And the vertical line 6x-8y+3=0.

So the slope is multiplied by =- 1.

And 6x-8y+3=0.

The slope of is k = 3/4.

So the slope of this linear equation is minus four-thirds.

So the linear equation is y-2= minus 4(x-3 (x-3)).

Y-2=4-3 4x

3y-6- 12+4x=0

3y+4x- 18=0