Move a cherry in the corner to the middle of the edge, leaving a calculated "blank" and move a cherry in the middle to this blank. Add 1, and then reduce the duplicate count accordingly. In fact, the middle number can be any number between 1 and 10. As long as the initial total number of four corners is not less than the middle number, it can be moved in this way to keep the count of each side at eight (the last four corners can be empty).
analyse
In the first operation, we first put the middle 1 in the third box from top to bottom on the left. At this time, the left * * * is 9, 1 more; So I took 1 from the fourth grid on the left (the grid on the corner) and put it in the second grid from left to right at the bottom. I thought of the bottom edge, moving from left to right 1, 8 unchanged.
In addition, the top and right sides did not participate in the operation just now, so there are still 8 cherries on the four sides.