Forget it, I'll write some programs for you.

1.(5x 2-2x- 1)/(5x 2-2x-5)=(5x 2-3x-5+x+4)/(5x 2-3x-5+x)=(x+4)/x。 )

2.(a+b) 2 = 8ab, (a-b) 2 = (b-a) 2 = 4ab, and a >；; B>0, so (a+b) under the radical number a+b)= 8ab, and (b-a) under the radical number is 4ab, so (a+b)/(b-a) under the radical number is 2.

3.x and Y are definitely not zero, so the formula (2x-14xy-2y)/(x-2xy-y) = (2/y-14-2/x)/(1/y-2-65438).

4. it won't ...

5.x=2(x cannot be equal to-1)

6.( 1) y=m(2)+n(2)=(m+n)*2=2

(2) Yes.

"the intersection of function y=a 1x+b 1 and function y=a2x+b2 is p" means that p satisfies two equations. Let P(p, q), so q=a 1p+b 1=a2p+b2.

Are you satisfied? ~