AC = radical 2AB, AO=OC (the nature of parallelogram)

∴AC=2AO

∴AB= root number 2AO

∴AB:AO=AC:AB= radical number 2

Once again ∠BAC=∠OAB

∴△BAC∽△OAB

∴∠ABD=∠ACB

∵ABCD is a parallelogram.

∴∠DAC=∠ACB

∴∠ABD=∠DAC

In BC,

∴AE/EB=AD/DC

∫sδADE/sδEBD = AE/EB，sδADB/sδDBC = AD/DC

Let S△EBD=S

Then 3/S=(3+S)/ 18.

S^2+3S-54=0

(S+9)(S-6)=0

S=-9 and S=6.

So S△EBD=6.