a^2+b^2=c^2 ①

a+b={(√3+ 1)/2}c ②

② a 2+2ab+b 2 = ( 1+√ 3/2) c 2。

That is, a 2+2ab+b 2 = (1+√ 3/2) (a 2+b 2).

Then simplify and factorize, and get:

(√3a-b)(a-√3b)=0

A is greater than B, so A is greater than B, so a=√3b holds.

Then substitute ② to get b= 1/2c.

So we get a=√3/2c.

b= 1/2c

C is C.

Then using the previous cosine theorem, we get that A is 60 degrees and B is 30 degrees.