So I'm vertical c1m.
Because ABC-a1b1c1is a regular triangular prism.
So ABC is a regular triangle.
BB 1 vertical ABC
So BB 1 vertical AM
And because BB 1 intersects with c1m.
So AM is perpendicular to the surface BCC 1B 1.
So AM is perpendicular to BC
So AM is the center line of ABC.
So m is the midpoint of BC.
ABC is a regular triangle, which mainly proves that AM is perpendicular to AM, so AM is a vertical line, that is, the middle line.
(2) Make a vertical line from point C to C 1M, with the focus of d, that is, CD is perpendicular to c1m..
Because AM is perpendicular to the surface BCC 1B 1.
I am also a vertical CD.
And because C 1M vertical CD.
AM and C 1M intersect at m.
So the vertical plane of CD AMC 1
That is, CD is the distance from point C to AMC 1.
The length of CD should not be difficult to calculate.