Solution: Assuming that B and C intersect at point D, this problem can be solved by using proportional knowledge.
① First calculate the length of the CD.
When Party B meets Party C, Party B's CD is 18km.
When A catches up with B, line B CD line C 18+32 = 50km.
Then 18: CD = CD: 50, CD×CD= 18×50=30×30.
So the length of the CD is 30 kilometers.
② Calculate the length of AC again.
C line 50+30 = 80km, A line AC.
The length of line C is 32km, and the BC of line A is 30+ 18=48.
So 32: 48 = 80: AC
Therefore, the length of AC is 80 ÷ 32/48 = 120km.
Two people, Party A and Party B, produce a batch of parts. The efficiency ratio of Party A and Party B is 2: 1. Co-shoot for three days, and Party B will shoot alone for the other two days. At this time, Party A produces 14 more parts than Party B. How many parts are there in this batch?
Solution: Take the work efficiency of B as the unit 1.
Then a's work efficiency is 2.
B 2 days to complete 1×2=2.
Otsuichi * * * produces 1×(3+2)=5.
A * * * Output 2×3=6
So the work efficiency B = 14/(6-5)= 14/ day.
A's work efficiency = 14×2 = 28/ day.
A * * * has 28×3+ 14×5= 154 parts.
Or let the work efficiency of Party A and Party B be 2a/ day and A/ day respectively.
2a×3-(3+2)a= 14
6a-5a= 14
a= 14
A * * * has 28×3+ 14×5= 154 parts.