Solution: According to the meaning, DB= 1/2AB=2.5.
because
BC=2AB (known)
therefore
BC= 10 (equivalent substitution)
because
DC=DB+BC
therefore
DC= 12.5 (properties of the equation)
2. In the Rt triangle ABC, two acute bisectors AO and BO intersect at point O, and the degree of angle AOB is found.
Solution: Angle A+ Angle B = 90
Angle OAB+ Angle Oba = (Angle A+ Angle B)/2=45.
Angle AOB= 180- Angle OAB- Angle OBA= 135.
3. In triangle ABC, the bisector of angle A and angle B intersect at point O, and when angle C is equal to several degrees, angle AOB=3. Angle c?
Solution: Angle A+ Angle B = 90
Angle OAB+ Angle Oba = (Angle A+ Angle B)/2=45.
Angle AOB= 180- Angle OAB- Angle OBA= 135.