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Please refer to the second volume of the fifth grade math problem.
Solution: Let the original rectangular lawn be A long and B wide.

The original area is ab.

When the length of both sides is increased by 1/3, the length is (1+ 1/3)a and the width is (1+1/3) b. 。

Then the new lawn area is (1+1/3) a× (1+1/3) b.

=4/3 a × 4/3 b

= 16/9 ab

16/9 ab - ab = 7/9 ab

The area of the new lawn has increased by 7/9 ab ÷ ab = 7/9.

I hope it helps you!