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Kneel for the master! ! ! mathematical
PA is perpendicular to the plane ABC where the circle o lies.

∴BC⊥PA

∫AB is the diameter of the circle O, and C is the point on the circle O..

∴BC⊥AC

∫PA∩AC = A

∴BC⊥ Plane packaging

∫AF, PC in the plane PAC.

∴AF⊥BC,BC⊥PC

∵AF⊥PC

BC∩PC=C

∴AF⊥ Plane PBC

∵PB in PBC plane

∴PB⊥AF

∵PB⊥AE,AE∩AF=A

Pb ⊥ Aircraft Company

∴PB⊥EF

∴∠FEP=90?

BC⊥PC,∠PCB=90? ,∠BPC=∠EPF

∴ Triangle PEF is similar to triangle PBC.