1/(110+112) = 5 and 5/ 1 1, that is, both of them have not finished working for five hours.

At this time, the remaining workload is 5/1* (110+112) =112.

1/ 12- 1/ 10 * 1/2 = 1/30,

B It takes1/30/112 = 2/5 hours.

A * * * takes 5+5+ 1/2+2/5= 10 and 9/ 10 hours.

Let the train be x meters long and y meters/second.

22y=x+22

26y=x+3*26

The solution is x=330.