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The first volume of the eighth grade is a complete math problem.
Passing through point e, EH, parallel AC, BC and h,

Then there is ∠EHB=∠BCA, ∠ HED = ∠ F.

AB = AC

∴∠B=∠BCA,

∴∠EHB=∠B

∴EH=EB

And EB=CF

∴EH=CF

∠EDH=∠FDC again

∠HED=∠F

∴△EDH is equal to △ △FDC.

So ED=FD