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Three problems in junior high school mathematics (about junior high school summer homework)
(1)√3- 1, absolute value √ 3-1; Or 0.732, with an absolute value of 0.732.

Note: The square root of 3 is 1.732.

(2) the square root of b is 3, and b=9, which is determined by AB >; 0 knows, a>0. Then a=5. That is, a-b=-4.

(3) Connect EF, let ∠CFO=∠ 1, ∠CEO=∠2,

In the triangle EFC ∠ FEC+∠ EFC =180-132 = 48,

In the triangle EOF, ∠ EOF = 180-∠ FeO-∠ Efo.

= 180-(∠FEC+∠EFC)-(∠ 1+∠2)

= 180 -48 -(∠ 1+∠2)

= 132 -(∠ 1+∠2)

= 132 - 1/2(∠CEA+∠CFA)

In the triangle ECB, 180 = ∠ CEA+∠ ECB+∠ EBC.

=∠CEA+( 180-∠ECF)+(∠CFA+∠A)

=∠CEA+∠CFA+( 180- 132)+58

Therefore: ∠ CEA+∠ CFA = 74

De: 1/2 (∠ CEA+∠ CFA) = 37。

Namely: ∠ EOF = 95.