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Mathematical problems of peaches
If you add one to this pile of peaches, you will get 2, 3, 4, 5, 6, 7, 8, 9, 10 at a time.

So finding the least common multiple of 2, 3, 4, 5, 6, 7, 8, 9, 10 and subtracting 1 is the step of this pile of peaches.

The least common multiple of 2, 3, 4, 5, 6, 7, 8, 9, 10 is:

2*3*5*7*2*2*3=2520

So the number of peaches in this pile is: 2520- 1=25 19.