( 1)x/3-x-4/3 = 1 2x-3x+ 12 = 6-x =-6 x = 6
(2)x/3 = 1+5-3x/2 2x = 6+3(5-3x) 1 1x = 2 1x = 2 1/ 1 1
(3)x-3/3- 1/2 = 4 2x-9 = 24 2x = 33 x = 33/2
(4)3y- 1/4- 1 = 5y-7/6 9y-3- 12 = 10y- 14-y = 1y =- 1
(5)2x/3+ x/2=28 4x+3x=28 7x=28 x=4
(6)5-x/4-6-2x/4 = 10 5-x-6+2x = 10 x = 1 1
(7)y-2/6 = y/3+ 1y-2 = 2y+6-y = 8y =-8
(8)y/3- y-2/6= 1 2y-y+2=6 y=4
(9)x/2=x/3 + 1 3x=2x+6 x=6
( 10)x+ 1/3 = x-2/2 2x-3x = 3x-6-x =-8 x = 8
Only these, I hope to help you!
The mathematical solution of the first equation is1(x-1) = 2-51(x+2).
Multiply both sides by 10.
5(x- 1)=20-2(x+2)
5x-5=20-2x-4
5x+2x=20-4+5
7x=2 1
x=2 1/7
x=3
Find 50 denominators and use the answer to take the process 1 to solve the equation. (20 10 Meishan, Sichuan) Solve the equation:
answer
Solution: ................ (2 points)
To solve this whole equation, you get: ............... (4 points).
Proved to be the solution of the original equation.
The solution of the original equation is ......................... (6 points)
2.(20 10 Jiaxing, Zhejiang) (2) Solve the equation:
Answer (2),
After testing, the solution of the original equation is ... 4 points.
3.(20 10 Taizhou City, Zhejiang Province) (2) Solve the equation.
Answer (2) Solution:
.
Proved to be the solution of the original equation.
So the solution of the original equation is.
4.(20 10 Yiwu, Zhejiang) (2) Solve the fractional equation:
Answer (2)
Prove to be the root of the original equation.
5.(20 10 Chongqing) Solve the equation:
answer
Solution: Multiply the two sides of the equation and you get.
Tidy it up and bring it here.
Solve.
After testing, it is the solution of the original equation. So the solution of the original equation is.
6.(20 10 Fujian Dehua) (8 points) As shown in the figure, point A and point B are on the number axis, and their corresponding numbers are respectively equal to, and the distances between point A and point B are equal to the origin, so the numerical value is obtained.
Answer: According to the meaning of the question,
Solution:
Proved to be the solution of the original equation.
A: Omit.
7.(20 10 Suqian, Jiangsu) (full mark for this question) Solve the equation:
.
Solution: remove the denominator and get.
2x-3(x-2)=0
Solve this equation and get x =6.
Test: substitute =6 into x(x-2)=24≠0.
So x =6 is the solution of this equation.
8.(20 10 Jinan, Shandong) Solve the fractional equation:
-=0
Solution: After naming: 3x-(x+2)=0 Solution: x= 1 Test that x= 1 is the root of the original equation.
So the original equation has no solution.
9.(20 10 Wuxi Jiangsu) (1) Solve the equation:
Solution: (1) 2(x+3)=3x from the original equation.
∴x=6.
X=6 is the solution of the original equation.
The solution of the original equation is x=6.
10.(20 10 Shanghai) Solve the equation: ── 1 = 0.
Answer: x2-2 (x-1) 2-x (x-1) = 0.
2x2─5x+2=0,∴x 1=2,x2=.
After testing, x 1=2, x2= the solution of the original equation, ∴the solution of the original equation is x 1=2, x2=
1 1.(20 10 Hebei) Solve the equation:.
The answer is:.
Proved to be the solution of the original equation.
12.(20 10 Jiangxi) Solving Equation: All-in-one Entrance Examination Network
Solution to the answer: multiply the two sides of the equation, get, solve and test: at that time, it was the root of the original equation.
13.(20 10 Bazhong, Sichuan) Solution: Fractional equation:
The answer is named:
Proved to be the solution of the original equation.
14.(20 10 Changzhou, Jiangsu) Solve the equation.
answer
15.(20 10 Jingzhou, Hubei) Solve the equation:
Answer Solution: Denominator has been removed:
Finishing:
Prove to be the root of the original equation.
16.(20 10 Enshi Autonomous Prefecture, Hubei Province) Solve the equation:
Answer: denominator:
(3-x)- 1=x-4
x=3
Test: bring x = 3 into the common denominator x-4 and get x-4 ≠ 0.
So x = 3 is the solution of the original equation.
17.(20 10 Beijing) Solve the fractional equation:
Answer: 3-2x = x-2 if the denominator is removed.
Arrangement 3x=5
Solve x=
X= is the solution of the original equation.
So the solution of the original equation is x =.
18.20 10 Taian, Shandong) (2) Solve the equation:
Answer solution. (2) The original equation can be simplified as follows
∴
that is
∴.
19.(20 10 Harbin, Heilongjiang) Simplify first, and then find the algebraic expression.
The answer is: the original formula
while
Primitive formula
20.(20 10 Nanchang, Jiangxi) Solve the equation:
Answer: multiply both sides of the equation by the same number, and you will get
.
Solve.
Inspection: at that time ≠0.
Therefore, it is the solution of the original fractional equation.
2 1.(20 10 Xiaogan, Hubei) (the full mark of this question is 6)
Solve the equation:
Solution: Both sides of the equation are multiplied by the same.
........................, two points.
To understand this equation, you get
When x=2, it is the solution of the original equation with ................. score of 5.
The solution of the original equation is x = 2 ........................... 6 points.
22.(20 10 Zhenjiang, Jiangsu) (2)
Answer (2), (1)
, (2 points)
, (3 points) Quanpin Senior High School Entrance Examination Network
(4 points)
After testing, the solution of Zhongyuan equation. (5 points)
23.(20 10 Jiangjin, Chongqing) Solve the equation:
Solution: Remove the denominator and get 2 points.
Simplify:
If the transfer matters are merged, add 5 points.
It is not the solution of the original equation.
So the original equation has no solution ………………………………………………………………………………………………………………………………………………………………………….
24.(20 10 Heze, Shandong) Solve the fractional equation.
Answer (3) Multiply both sides of the original equation by 2-x to get: -( 1-x)+2 (2-x) = 1.
Solution: x = 2
The test shows that x = 2 is the root of the original equation.
So the original equation has no solution.
25.(20 10 Xining, Qinghai) Solve the fractional equation.
Solution: Multiply two sides of the equation by 2(3x- 1) to get 3(6x-2)-2=4.
18x-6-2=4
18x= 12
x=
Test: substitute x= into 2 (3x-1): 2 (3x-1) ≠ 0, ∴x= is the root of the original equation.
The solution of the original equation is x=
26.(20 10 Zunyi, Guizhou) Solution equation:+1=
Solution: Multiply both sides of the equation by (x-2) at the same time to get: …1minute.
(x-3)+x-2 =-3 4 points.
Merge: 2x-5 =-3 5 points.
2x = 2: 06.
∴x = 1 7 points.
After testing, x= 1 is the ....................................................... score of the original equation.
27.(20 10 Nanping, Fujian) Solve the equation: += 1.
Solution: Multiply both sides of the equation by (x+ 1) (x- 1).
x(x- 1)+2(x+ 1)=x2
The solution is x =-3.
It is verified that x =-3 is the root of the original equation.
The root of the original equation is x =-3.
28.(20 10 Dazhou, Sichuan) For algebraic sum, can you find a suitable value to make their values equal? Write down your problem-solving process.
Answer: Yes.
According to the meaning of the question, let =,
Then 2x+ 1=3(x-2).
Solution: x=7,
It is proved that x=7 is the solution of =.
Therefore, when x=7, the value of algebraic sum is equal.
29.(20 10 Panzhihua, Sichuan) Solve equation +3 =
Solution: The sorted score is+3 = …1,and the two sides are multiplied by x-2 to get … 2 points.
1+3 (x-2) = 1-x...3 points ∴ x =...4 points.
Test: when x =；; x-2 =-≠0； ∴x = is the root of the original equation.
The root of the original equation is x =..........................6 points.
Does anyone have an exercise in solving equations by denominator roll call in junior one mathematics? 1，4x+3/4- 2-3x/8=x？
Denominator: 2(4x+3)-(2-3x)=8x.
Transposition: 8x-8x+3x=-6+2
Merge: 3x=-4
The conversion coefficient is 1: x =-4/3.
2、3x+ 2x- 1/3=3- x+ 1/2
Denominator:18x+2 (2x-1) =18-3 (x+1)
Transfer item: 18x+4x+3x=2+ 18-3.
Merge: 25x= 17
The conversion coefficient is 1: x = 17/25.
3、 10x+ 1/6-2X- 1/3 = 1-2X+ 1/4
Denominator: 12 is multiplied at the same time to get 2 (10x+1)-4 (2x-1) =12-3 (2x+1).
Transfer item: 20x-8x+6x=-2-4-3+ 12.
Merge: 18x=3
The conversion coefficient is 1: x = 1/6.
4、2x- 1/3- 1=-5x+2/2
Denominator: 2(2x- 1)-6=-3(5x+2)
Transfer term: 4x+ 15x=2+6-6.
Merge: 19x=2
The conversion coefficient is 1: x = 2/ 19.
5、 1- 10x+ 1/6 = 2x+ 1/3
Denominator:1-(10x+1) = 2 (2x+1).
Transposition:-10x-4x =-1+1+2.
Merge:-14x=2
The conversion coefficient is 1:x=- 1/7.
6、7x-5/4=3/8
Denominator: Multiply left and right by 8 to get: 2(7x-5)=3.
Transfer item: 14x=3+ 10
Merge: 14x= 13
The conversion coefficient is 1: x = 13/ 14.
7、x/2- 5x+2/6= 1- 2x-4/3
Denominator: 3x-(5x+2)=6-2(2x-4)
Transposition: 3x-5x+4x=2+6+8
Merge: 2x= 16
The conversion coefficient is 1: x = 8.
8、3-x/2=x-4/3- 1
Denominator: 3(3-x)=2(x-4)-6.
Transposition: -3x-2x=-9-8-6
Merge: -5x=-23
The conversion coefficient is 1: x = 23/5.
9、5x- 1/4 = 3x+ 1/2-2-x/3
Denominator: Multiply left and right by 12 to get 3 (5x-1) = 6 (3x+1)-4 (2-x).
Transfer item: 15x- 18x-4x=3+6-8.
Merge: -7x= 1
The conversion coefficient is 1: x =- 1/7.
10、x- 3-2x/2= 1-x+2/6
Denominator: 6x-3(3-2x)=6-(x+2)
Transposition: 6x+6x+x=9+6-2
Merge: 13x= 13
The conversion coefficient is 1: x = 1.
How to solve the denominator of the equation in junior one mathematics? If it is an integral equation, both sides are multiplied by the least common multiple.
If it is a fractional equation, both sides are multiplied by the simplest common denominator at the same time
Urgent for solving equation (removing denominator) 30 questions in the first grade mathematics! 1. Solve equation 6x+ 1=-4, and the correct shift term is ().
A.6x = 4- 1 b .-6x =-4- 1 c . 6x = 1+4d . 6x =-4- 1
2. Solve the equation -3x+5=2x- 1, and the shift term is correct ().
a . 3x-2x =- 1+5 b .-3x-2x = 5- 1 c . 3x-2x =- 1-5d .-3x-2x =- 1-5
3. The following equation deformation is correct ()
A. from -2x = 6, x=3.
B.from-3 = x+2，x =-3-2。
C from-7x+3 = x-3，(-7+ 1) x =-3-3。
D x =- 1 from 5x = 2x+3.
4. It is known that when x = 2 and y = 1, the value of the algebraic expression KX-Y is 3, so the value of k is ().
A.2 B.-2 C. 1 D.- 1
The denominator removal problem of solving equations in the first grade of mathematics, (x-1)/2 = (4x+2)/5-2 (x-1).
5(x- 1)= 2(4x+2)-20(x- 1)
17x=29
x=29/ 17
What is the first mathematical solution of Equation 20?
The process of solving equations in the first grade mathematics is 43x-4]-3 [x-1= x-12x-16-3x+3 = x-19x-13 = x-65433.
2x- 1/3=x/3+2
6x- 1=x+6
5x=7
x=7/5
﹣x=2/5x+ 1
﹣7/5x= 1
x=﹣5/7