(a99- 1)/(a 100- 1)< 0。
Give the following conclusions:
①0 < q < 1;
②a99? a 10 1- 1 < 0;
③ The value of ③T 100 in TN is the largest;
④ Make the maximum natural number n of TN > 1 equal to 198.
The correct conclusion is ()
A.①②④ B.②④ C.①② D.①②③④
∵a99a 100- 1>0,∴a 12? q 197> 1,∴(a 1? q98)2> 1。
∵a 1> 1,∴q>0.
∫(a99- 1)/(a 100- 1)< 0,∴ A99 > 1,A 100 < 1。
∵a99? a 10 1=a 100^2; 0