Solution: the shape of water in the container is still a cone, so let the height of the cone be H.

According to the meaning of the question, it is obtained by V= 1/3*Sh.

5= 1/3*Sh

It can be observed that when filled with water, the water in the container is also conical.

And is easy to obtain; when the height of the water surface is half that of the container, the radius of the bottom surface of the cone is twice that of the cone storefront;

When the water is full, the radius of the water surface is 2r and the area is s'; when the water height is half full, the radius of the water surface is r and the area is s.

So by S=πr? Get: S'=4πr？ =4, when filled with water, the water level is H', and h'=2h.

So when filled with water, the volume of water is: 1/3*4S*2h=8*5=40.

The volume of water that this container can hold: 40-5=35L.