The solution set of the first equation is (-5, 1/2), and the solution set of the second group is: x >；; [(-3k-1+(9k2-2k-3)1/2]/2 or x; When there are two roots at 0, the discussion is as follows:

In the first case, one root is between (-4, -3) and the other root is >: =0. At this time, the meaning of the problem is satisfied because delta >；; 0, so k> [1+2 * (71/2)]/9 or k.

Then f (-4) >; 0，f(-3)& lt； 0，f(0)& lt； 0, substituting into the equation to get the solution: k has no solution, so this situation is not satisfied.

The second situation: the solution

Satisfy: f (-4)

The third case: when the equation has only one solution, the solution satisfying the meaning of the question does not hold.

So k>= 13/ 10, that's what you want.