Current location - Training Enrollment Network - Mathematics courses - Mathematical cross volume problem
Mathematical cross volume problem
The volume of the remaining cube is 4*4*4=64 cubic centimeters.

The original cuboid volume is 32+64=96 cubic centimeters.

The surface area can be calculated like this, because the rest are cubes, so it can be seen that one side of the cuboid of 32 is a square with a side length of 4, and the other side length is 32/(4*4)=2, so it can be seen that the original rectangle has 4, 4 and 6 sides respectively (because 4+2=6), and the surface area of the cuboid is (4 * 4+4 *).