In the process of (1) ball from A to O, according to the kinetic energy theorem: 12 mvo2 = mgl? qEl ①

Bring in the data and get the speed of the ball at point O: vo=2m/s? ②

(2) Newton's second law applies to the ball before it is transported to point O and the rope breaks: t? Mg? F Luo = =mvo2l ③

F Luo =Bvoq ④

② ③ ④ Simultaneously: T=8.2N ⑤

(3) After the rope is broken, the horizontal acceleration of the ball AX = F, M = EQM = 5m/S2? ⑥

It takes t=2v0ax=2×25s=0.8s ⑦ for the ball to move from point O to point N..

The distance between the openings? h= 12gt2=3.2m ⑧

A: When the ball moves to the O point, the speed is 2m/s, the instantaneous tension before the catenary breaks is 8.2N, and the distance between the ON points is 3.2m 。