The volume of the 8 cm high part of this ingot =3. 14*(R bucket) 2 * 4 = 12.56 (R bucket) 2.

Volume of ingot: the volume of the 8 cm high part of this ingot = the height of the ingot: 8.

28.26 (right bucket) 2: 12.56 (right bucket) 2 = h ingot: 8

H ingot = 8 * 28.26/12.56 =18cm.

The volume of this ingot = 3.14 * 5 * 5 *18 =1413 cubic centimeter.