Because the intersection of complement sets of set A and set B is-1 ≤ x < 1, and set A- 1 ≤ x < 2,
Just bring these directly into the competition one by one.
AC is all qualified, no problem.
The difference of BD lies in whether it is equal to-1.
Assuming that set B contains-1, then the complement of set B does not have-1, then the intersection of set A and the complement of set B does not have-1, which contradicts the topic, so set B does not have-1.
The answer should be D.