solve
The straight line L 1 is perpendicular to L2, and the slope of L2 is -4.
The slope of = =>L 1 is 1/4.
And L 1 crosses the origin.
The equation of = =>L 1 line is y=? x
L 1 and L2 intersect at point (t, t+ 1).
= = & gtt+ 1=? t……①
4t+(t+ 1)=k……②
= = & gtt=-4/3,k=- 17/3