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Sixth grade math travel questions;
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The hound jumped three times and the rabbit jumped four times.

Caption: At the same time, the hound advanced 4×3= 12 meters, and the rabbit advanced 2.2×4=8.8 meters.

Therefore, in unit time, hounds walk more than rabbits 12-8.8=3.2 (meters).

The original distance difference is 40 meters, and the time taken for the rabbit to be caught up is 40 ÷ 3.2 = 12.5.

The distance that the rabbit ran out was =12.5× 8.8 =110 (m).