Clockwise 12 hour, 1 cycle, 30 degrees per hour, 0.5 degrees per minute; The minute hand walks every hour 1 lap, 6 degrees per minute. Therefore, if we take 0 degrees at 0: 00: 00, at 2: 00 m, the angle of the hour hand is (30×2+0.5M) degrees, and the angle of the minute hand is 6M degrees. The angle between two needles is equal to the angle difference between two needles, that is, 6m-(60+0.5m) = 5.5m..

According to the question, it means 5.5M-60= 60 = 60.

When the right side of the equal sign is+,the solution is m =120/5.5 = 21.8 ≈ 22 points.

When the right side of the equal sign is-,the solution is M=0.

Therefore, from 2 o'clock to 3 o'clock on the clock face, the angle between the hour hand and the minute hand is 60 degrees twice; It's 2 o'clock sharp and 2: 22 respectively.