Let the volume of water in the bottle be v and the volume of spare parts in the bottle be V 1.
There are:
V
+
V 1
=
1L (total volume in the bottle)
Let the inner radius of the bottle body part be r and the inner bottom radius of the cylindrical cup be r.
There are:
V
/
Pi*R*R
=
2 (When the bottle is placed upright, the water level is lower than 2 decimeters)
V 1
/
Pi*R*R
=
0.5 (when placed upside down, the height of spare parts is less than 0.5 decimeter)
The volume v of water can be solved by the above three equations:
V
=
0.8 liter
Then look inside the cylindrical glass:
V
/
Pi*r*r
=
1 (the water level in the cylindrical cup is 1 decimeter high)
According to this equation, the inner bottom area r of cylindrical water cup can be obtained:
r
=
5.05 cm
(Note: 1. In the expression here, it is difficult to find the symbol of hesitation Pi, and it is also difficult to find a single toilet, so it is directly replaced by pi;
2. unit of volume 1 liter is equal to 1 cubic decimeter, so it is more convenient for me to convert the length unit into decimeter. )